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In the nuclear reaction U92^238 to Pb82^...

In the nuclear reaction `U_92^238 to Pb_82^206`, the number of alpha and beta particles decayed are:

A

`4 alpha, 3 beta`

B

`8 alpha, 6 beta`

C

`6alpha , 4 beta`

D

`7 alpha , 5 beta`

Text Solution

Verified by Experts

The correct Answer is:
B
Number of `alpha`-particle `=(238-206)/(4) = 8`
number of `beta`-particles `= 2 xx 8 - 92 + 82 = 6`
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