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Consider the following nuclear reactions...

Consider the following nuclear reactions:
`""_(92)""^(238)Mto.""_(y)""^(x)N+2.""_(2)""^(4)He, ""_(x)""^(y)Nto ""_(B)""^(A)L+2beta""^(+)`
The number of neutrons in the element L is

A

140

B

144

C

142

D

146

Text Solution

Verified by Experts

The correct Answer is:
B

`""_(92)M^(238) to ""_(y)N^x + 2 ""_(2)He^4 `
`""_(y)N^x to ""_(B)L^A + 2 beta^+`
`""_(y)N^x = ""_(92-2xx2)N^(238-2xx2) = ""_(88)N^(230)`
`""_(88)N^(230) overset(2beta^+)to ""_(88-2)L^((230)) = ""_(86)L^(230)`
Total no. of neutrons in `""_(86)L^(230)`
230 - 86 = 144
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