Molecular weight of oxalic acid is 126. the weight of oxalic acid required to neutralise 100cc of normal solution of NaOH is

Options

A. 6.3 g
B. 126 g
C. 530 g
D. 63 g

Answer

A

Explanation

`N = (W_(B) xx 1000)/(Eq. wt xx N)`
` Eq = (1 xx 63 xx 100)/(1000)`
` = 6.3 g`