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How many moles of NaOH is required to ne...

How many moles of NaOH is required to neutralize 1 mole of `H_(3)PO_(3)`

A

`1 L - N - H_(2)SO_(4)`

B

`1 L - M - H_(2)SO_(4)`

C

`1 L - 2N - H_(2)SO_(4)`

D

`1 L - 0.5 N - H_(2)SO_(4)`

Text Solution

Verified by Experts

The correct Answer is:
A
`N_(1)V_(1) = N_(2)V_(2) rArr 1 xx 1 = 1 xx 1`
`1N - H_(2)SO_(4)` have the same normality so `1L - N - H_(2)SO_(4)` , neutralise `1L, N - NaOH`
as 0.5 N will give double the amount of `H^(+)` ions.
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