100 mL of 0.5 N NaOH solution is added t...

100 mL of `0.5` N NaOH solution is added to 10 mL of 3 N `H_(2)SO_(4)` solution and 20 mL of 1 N HCl solution . The mixture is

A

100 mL

B

150 mL

C

200 mL

D

250 mL

Verified by Experts

The correct Answer is:

B

`N_(1)V_(1) = N_(2)V_(2)`
`4 xx 50 = 1 xx V_(2)`
`V_(2) = 20 mL`
Volume added should be = 200 − 50 mL = 150 mL .

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