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The volume of 0.1M Ca(OH)(2) required to...

The volume of 0.1M `Ca(OH)_(2)` required to neutralize 10 mL of 0.1 N HCl

A

10mL

B

20mL

C

5mL

D

15mL

Text Solution

Verified by Experts

The correct Answer is:
C
`because N = M xx z`
` = 0.1 xx 2 = 0.2` for `Ca(OH)_(2)`
` because N_(1)V_(1) = N_(2)V_(2)`
`therefore 0.2 xx V_(1) = 0.1 xx 10`
`therefore V_(1) = (0.1 xx 10)/(0.2) = 5mL`
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