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What volume at N.T.P. of gaseous NH(3) w...

What volume at N.T.P. of gaseous `NH_(3)` will be required to be passed into 30 ml of `N-H_(2)SO_(4)` solution to bring down the acid strength of this solution to 0.2 N

A

357.2 mL

B

444.4 mL

C

537.6 mL

D

495.6 mL

Text Solution

Verified by Experts

The correct Answer is:
C
Acid neutralized by `NH_(3)` = 30mL of
`N- H_(2)SO_(4) - 0.2N H_(2)SO_(4) = (30 xx 0.8 xx 17)/(1000)` g
Since 17 g of `NH_(3)` at N.T.P occupies 22.4L
` therefore (30 xx 0.8 xx 17)/(1000) g` of `NH_(3)` at N.T.P occupies
` = (22.4)/(17) xx (30 xx 0.8 xx 17)/(1000)` = 0.5376L = 537. 6 mL
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