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25 ml of a solution of Na(2)CO(3) having...

25 ml of a solution of `Na_(2)CO_(3)` having a specific gravity of 1.25 required 32.9 ml of a solution of HCl containing 109.5 grams of the acid per litre for complete neutralization. Calculate the volume of 0.84N-`H_(2)SO_(4)` that will be completely neutralized by 125 grams of the `Na_(2)CO_(3)` solution

A

460 mL

B

540 mL

C

480 mL

D

470 mL

Text Solution

Verified by Experts

The correct Answer is:
D
`N_(1)V_(1) = N_(2)V_(2)`
`N xx 25 = (109.5 xx 32.9)/(36.5) rArr N = (109.5 xx 32.9)/(36.5 xx 25)`
`N_(3)V_(3) = N_(4)V_(4) (V_(3) = (m)/(d), V_(3) = ( 125)/(1.25))`
` (109.5 xx 32.9)/(36.5 xx 25) xx 100 = 0.48 xx V rArr V = 470 mL`
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