Home
Class 12
CHEMISTRY
20 ml of a solution of a weak monobasic ...

20 ml of a solution of a weak monobasic acid neutralizes 22.18 ml of solution of NaOH and 20 ml of N/10 HCl neutralizes 21.5 ml of the same NaoH solution. The normality for the acid is nearly

A

10 N

B

1 N

C

0.10 N

D

100 N

Text Solution

Verified by Experts

The correct Answer is:
C
`N_(1)V_(1) = N_(2)V_(2)`
`N_(1) xx 20 = N_(2) xx 22.18`
`N_(1) = (N_(2) xx 22.18)/(20)`
NaOH solution = HCl solution.
`N_(2) xx 21.5 = (1)/(10) xx 20`
`N_(2) = (20)/(10 xx 21.5)`
By eq. (i) and (ii)
`N_(1) = (20 xx 22.18)/(20 xx 10 xx 21.5) = (22.18)/(215) = 0.1N`
Promotional Banner

Similar Questions

Explore conceptually related problems

10 mL of a solution of NaOH is found to be completely neutralised by 8 mL of a given solution of HCl. If we take 20 mL of the same solution of NaOH, the amount HCl solution (the same solution as before) required to neutralise it will be (i) 4 mL (ii) 8 mL (iii) 12 mL (iv) 16 mL

20 ml of 1/3 M solution of acid is required to neutralise 0.8 M, 25 ml NaOH solution. Hence, basicity of acid is:

What is the strength in g//L of a solution of H_(2)SO_(4), 14 mL of which neutralized 20 mL of N//10 NaOH solution?

What is the strength in g per litre of a solution of H_(2)SO_(4), 12 mL of which neutralized 15 mL of N//10 NaOH solution?