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20 ml of 1 N solution of KMnO(4) just re...

20 ml of 1 N solution of `KMnO_(4)` just reacts with 20 ml of a solution of oxalic acid. The weight of oxalic acid crystals in 1N of the solution is

A

31.5 g

B

126 g

C

63 g

D

6.3 g

Text Solution

Verified by Experts

The correct Answer is:
C
`20 mL N KMnO_(4)~= 20 mL` N oxalic acid
`therefore ` Normality of oxalic acid solution = 1 N
as ` W = ( "NEW")/(1000) = (1xx 63 xx 1000)/(1000)`
= 63g.
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