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Weight of Ca(OH)(2) needed to prepare 25...

Weight of `Ca(OH)_(2)` needed to prepare 250 ml of solution with pH=13

A

0.925 g

B

0.0125 g

C

0.25 g

D

1 g

Text Solution

Verified by Experts

The correct Answer is:
A
We Know `[H^(+)] = 10^(-pH) = 10^(-13)`
`therefore [OH^(-)] = (10^(-14))/(10^(-13)) = 10^(-1)`
Hence, normality of solution = 0.1
We know, w ` = ("NEW")/(1000) = (0.1 xx 74 xx 250)/(2 xx 1000) = 0.925 g`
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