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What is the molarity of H(2)SO(4) soluti...

What is the molarity of `H_(2)SO_(4)` solution if 25 ml of exactly neutralised with 32.63 ml of 0.164M, NaoH

A

0.107 M

B

0.126 M

C

0.214 M

D

`– 0.428 M`

Text Solution

Verified by Experts

The correct Answer is:
A
`0.164 M NaOH ~= 0.164 N NaOH`
We know, `N_(1)V_(1) = N_(2)V_(2), N_(1) xx 25 = 0.164 xx 32.63`
`0.214 N H_(2)SO_(4) ~= (0.214)/(2) M H_(2)SO_(2)`
( `because` basicity of `H_(2)SO_(4)` is 2)
`~= 0.107 M H_(2)SO_(4)`
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