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A solution containing Na(2)CO(3) and NaO...

A solution containing `Na_(2)CO_(3)` and `NaOH` requires `300 ml` of `0.1 N HCl` using phenolphthalein as an indicator. Methyl orange is then added to the above titrated solution when a further `25 ml` of `0.2 N HCl` is required. The amount of `NaOH` present in solution is `(NaOH=40, Na_(2)CO_(3)=106)`

A

0.5 g

B

1 g

C

2 g

D

4 g

Text Solution

Verified by Experts

The correct Answer is:
B
First 300 mL of 0.1 N HCl neutralises the entire amount of NaOH and 1/2 of `Na_(2)CO_(3)`
As given, 25 mL of 0.2 N HCl neutralises remaining 1/2 of `Na_(2)CO_(3)` = 50 mL of 1.0 N HCl
So number of milliequivalents of HCl = no. of milliequivalents of NaOH
Eq. vol. for neutralization = 300 − 50 = 250mL
250 × 1.0 N HCl = 250 × 1.0 N NaOH
which is equal to 1 g of NaOH.
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