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What will be DeltaH for the reaction, ...

What will be `DeltaH` for the reaction,
`CH_(2)Cl_(2)rarrC+2H+2Cl`?
(B.E. of `C-H` and `C-Cl` bonds are `"416 kJ mol"^(-1)` and `"325 kJ mol"^(-1)` respectively)

A

0.7 g

B

1.4 g

C

2.8 g

D

5.6 g

Text Solution

Verified by Experts

The correct Answer is:
B

50% of reagent used by 50% of 6.45 g. `CH_(3)CH_(2)Cl`
Hence `(6.45)/(2)` g = 3.22g of `CH_(3) CH_(2)Cl` Consumed.
`underset((64.5g))(CH_(3)CH_(2)Cl)overset("reagent") to underset("(28g)")(CH_(2)) = CH_(2) + H^(+)Cl^(-)`
`therefore ` 64.5 g `CH_(3)CH_(2)Cl` produce ethene ` = 28 g `
`therefore` 3.22 g `CH_(3)CH_(2)Cl` produce ethene ` = (28g xx 3.22 g)/(64.5g)`
` = 1.39g ~~ 1.4g`
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