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If we use phenolphthalein as an indicato...

If we use phenolphthalein as an indicator in a titration of `Na_(2)CO_(3)` with HCl, the usual result is

A

`K_(4)Fe(CN)_(6)`

B

`K_(3)Fe(CN)_(6)`

C

Phenolphthalein

D

Methyl orange

Text Solution

Verified by Experts

The correct Answer is:
D
`Na_(2)CO_(3) + HCl to NaHCO_(3) + NaCl`
Methyl orange will change for the second protonation :
`NaHCO_(3) + HCl to H_(2)CO_(3) + NaCl`
`H_(2)CO_(3) to H_(2)O + CO_(2)`
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