The equivalent weight of `Zn(OH)_(2)` is the following reaction is equal to its, `[Zn(OH)_(2)to(NO_(3))toZn(OH)(NO_(3))+H_(2)O]`

Options

A. `("Formula wt.")/(2)`
B. `("Formula wt")/(1)`
C. `3 xx "formula wt"`
D. `2 xx "formulawt".`

Answer

B

Explanation

Equivalent weight of
`Zn(OH)_(2) = ("Molecular weight")/("acidity") = (M)/(1)`
Acidity of `Zn(OH)_(2)` = 1 , only one OH is replaced.