Home
Class 12
CHEMISTRY
1 litre solution containing 490 g of sul...

1 litre solution containing 490 g of sulphuric acid is diluted to 10 litre with water. What is the normality of the resulting solution ?

Text Solution

Verified by Experts

The correct Answer is:
1

As `N_(1)V_(1) = N_(2)V_(2)`
` (490)/(49) xx 1 = N_(2) xx 10`
`N_(2) = (49)/(49 xx 10) = 1N`
Promotional Banner

Similar Questions

Explore conceptually related problems

0.5M of H_(2)SO_(4) is diluted from 1 litre to 10 litre, normality of resulting solution is

250 mL of 1.5 M solution of sulphuric acid is diluted by adding 5L of water. What is the molarity of the diluted solution ?

A 5 molar solution of H_(2)SO_(4) is diluted from 1 litre to 10 litres. What is the normality of the solution?

0.5 M of H_(2)SO_(4) is diluted from 1 litre to 10 litre, normality of resulting solution is

pH calculation upon dilute of strong acid solution is generally done by equating n_(H) in original solution & diluted solution.However . If strong acid solution is very dilute then H^(+) from water are also to be considered take log3.7=0.568 and answer the following questions. A 1 litre solution of pH=6 (solution of a strong acid) is added to the 7//3 litres of water.What is the pH of resulting solution? Neglect the common ion effect on H_(2)O .

A 5 molar solution of H_2SO_4 is diluted from 1 litre to a volume of 10 litres , the normality of the resulting solution will be :

The density of a solution containing 13% by mass of sulphuric acid is 1.09 g..mL . Calculate the molarity and normality of the solution.