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0.7 g " of " Na(2)CO(3).xH(2)O were diss...

`0.7 g " of " Na_(2)CO_(3).xH_(2)O` were dissolved in water and the volume was made to `100 mL, 20 mL` of this solution required `19.8 mL " of " N//10 HCl` for complete neutralization. The value of `x` is:

Text Solution

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The correct Answer is:
2
` 2 xx (0.7)/(106 + 18x) =5 xx 19.8 xx (1)/(10) xx (1)/(100)`
On solving , we get x = 2
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