The ion that cannot be precipitated by both HCl and `H_2 S` is

Options

A. `Pb^(2+)`
B. `Cu^(+)`
C. `Ag^(+)`
D. `Sn^(2+)`

Answer

D

Explanation

`PbCl_(2)` is insoluble in HCl and PbS is insoluble in `H_(2)S`.
`Cu^(+)Cl^(-)(CuCl) ` and `Cu^(+)S^(2-)(Cu_(2)S)` are insoluble.
AgCl and `Ag_(2)S` are insoluble.
`SnCl_(2)` is soluble but SnS is insoluble.
Hence, `Sn^(2+)` can be precipitated by `H_(2)S` but not by HCl.