The compound that will react most readily with `NaOH` to from methanol is

Options

A. `(CH_3)_4N^(+)I^(-)`
B. `CH_(3)OCH_(3)`
C. `(CH_3)_3S^(+)I^(-)`
D. `(CH_3)_3Cl`

Answer

A

Explanation

Electronegativity of `N gt S`
So positive charges on nitrogen will make methyl group more electron deficient than positive charge on sulphur, therefore `(CH_3)_4N^+ I^-` will undergo `S_(N^2)` reaction more rapidly.
`NaOH + [CH_3-overset(CH_3)overset(|)underset(CH_3)underset(|)N-CH_3]^(+)I^(-) rarr CH_(3)OH + (CH_3)_3N + Nal`