Compound (A) undergoes Cannizzaro reaction and (B) undergeos positive iodoform test. Therefore

Options

A. A = Acetaldehyde , B = 1-Pentanal
B. A = `C_6H_5CH_2CHO` , B = 3-Pentanone
C. A = Formaldehyde , B = 2-Pentanone
D. A = Propionaldehyde , B = 1-Pentanol

Answer

C

Explanation

Aldehydes having no `alpha`-H on heating with conc. alkali undergo disproportionation, known as Cannizzaro reaction. Ketones do not give this reaction. Compounds containing `CH_3 - CO` group or `CH_3 - CH - OH` group give positive iodoform test. Among the given options, only option (c) i.e. HCHO and `CH_3CH_2CH_2COCH_3` respond to the respective reactions.