The enol form of acetone after treatment with `D_(2)O` gives:

Options

A. `CH_3-overset(OD)overset(|)C=CH_2`
B. `CD_3-overset(O)overset(||)C-CD_3`
C. `CH_2=overset(OH)overset(|)C-CH_2D`
D. `CD_2=overset(OD)overset(|)C-CD`

Answer

B

Explanation

`underset("Acetone (ketoform)")(CH_3-overset(O)overset(||)C-CH_3)[underset("enol form")(CH_3-overset(OH)overset(|)C=CH_2)] harr`
`CH_3-overset(OD)overset(|)C=CH_2 harr CH_3-overset(O)overset(||)C-CH_2D harr`
`CH_2=overset(OH)overset(|)C-CH_2D overset(D_2O)harr CH_2=overset(OD)overset(|)C-CH_2D harr`
`DCH_2-overset(O)overset(||)C-CH_2D` `D_3C-overset(O)overset(||)C-CD_3`
The enol form of acetone on treatment with `D_2O` undergoes enolisation, deutration (addition of `D_2O` ) and dehydration (removal of `H_2O`). The repeated enolisation, deutration and dehydration ultimately gives `CD_3 . COCD_3`.