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CH3 CH=CHCHO is oxidised to CH3 CH=CHCOO...

`CH_3 CH=CHCHO` is oxidised to `CH_3 CH=CHCOOH` using :

A

Alkaline `KMnO_4`

B

Selenium dioxide

C

Ammoniacal `AgNO_3`

D

All of these

Text Solution

Verified by Experts

The correct Answer is:
C
`CH_3CH=CHCHO+2[Ag(NH_3)_2]^(+) rarr 2Ag+4NH_3+CH_3CH=CHCOOH+H_2O`
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