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If (log)k xdot(log)5k=(log)x5,k!=1,k >0,...

If `(log)_k xdot(log)_5k=(log)_x5,k!=1,k >0,` then `x` is equal to
(a) `k` (b) `1/5` (c) 5 (d) none of these

A

k

B

`(1)/(5)`

C

5

D

None of these

Text Solution

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The correct Answer is:
B, C
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