If n=1983!, then the value of expression...

If `n=1983!`, then the value of expression `(1)/(log_(2)n)+(1)/(log_(3)n)+(1)/(log_(4)n.)+......+(1)/(log_(1983)n)` is equal to

A

`-1`

B

0

C

1

D

2

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The correct Answer is:

C

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