If z^(2)+(p+iq)z+(r+is)=0, where,p,q,r,s...

If `z^(2)+(p+iq)z+(r+is)=0`, where,p,q,r,s are non-zero, has real roots, then

A

`pqr =r^2 +p^2 s`

B

`prs = q^2 + r^2 p`

C

`qrs =p^2 + s^2q`

D

`pqs = s^2 + q^2r`

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The correct Answer is:

D

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