If z=sintheta-icostheta then for any i...

If ` z=sintheta-icostheta` then for any integer n,

A

`z^n+1/z^n=2cos((npi)/2-ntheta)`

B

`z^n+1/z^n=2sin((npi)/2-ntheta)`

C

`z^n-1/z^n=2isin(n theta - (npi)/2)`

D

`z^n-1/z^n=2icos((npi)/2-n theta)`

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The correct Answer is:

A, C

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