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If omega (!= 1) is a cube root of unity,...

If `omega (!= 1)` is a cube root of unity, then the sum of the series `S = 1 + 2omega + 3omega^2 + ..... + 3nomega^(3n-1)` is

A

`(3n)/(omega-1)`

B

`3n(omega-1)`

C

`(omega-1)/(3n)`

D

0

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The correct Answer is:
A
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