The roots of the given equation (p - q) ...

The roots of the given equation `(p - q) x^2 + (q -r ) x + (r - p)=0` are

A

`(p-q)/(r-p),1`

B

`(q-r)/(p-q),1`

C

`(r-p)/(p-q),1`

D

`1,(q-r)/(p-q)`

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

The roots of the equation (q-r)x^(2)+(r-p)x+(p-q)=0

If p, q, r are real and p ne q , then the roots of the equation (p-q)x^(2) +5(p+q) x-2(p-q) r are

If p,q and r are rational numbers, then the roots of the equation x^(2) - 2px + p^(2) + 2 qr - r^(2) = 0 are

The roots of the equation (x-p) (x-q)=r^(2) where p,q , r are real , are

If p,q are real p!=q, then show that the roots of the equation (p-q)x^(2)+5(p+q)x-2(p-q)=0 are real and unequal.