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The least value of 2x^2 + y^2 + 2xy + 2...

The least value of `2x^2 + y^2 + 2xy + 2x-3y + 8` for real number x and y is

A

`-4/3,2`

B

`-(3)/(2),4`

C

`-(7)/(2),2`

D

`-(5)/(2),4`

Text Solution

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The correct Answer is:
D
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