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Let Pm stand for mPm then 1+P1+2P2+3P...

Let `P_m` stand for `mP_m` then `1+P_1+2P_2+3P_3+.......+nP_n` is equal to

A

`n!`

B

`(n+3)!`

C

`(n+2)!`

D

`(n+1)!`

Text Solution

Verified by Experts

The correct Answer is:
D
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