If sintheta+sin2theta+sin3theta=sinalpha...

If `sintheta+sin2theta+sin3theta=sinalpha` and `costheta+cos2theta+cos3theta=cosalpha` , then `theta` is equal to

A

`alpha//2`

B

`alpha`

C

`2alpha`

D

`alpha//6`

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The correct Answer is:

A

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