If sin(theta+phi)=nsin(theta-phi), then ...

If `sin(theta+phi)=nsin(theta-phi)`, then the value of `tantheta/tanphi` is equal to

A

`(n)/(n-1)`

B

`(n+1)/(n-1)`

C

`(n)/(1-n)`

D

`(n-1)/(n+1)`

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The correct Answer is:

B

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