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If cosA=mcosB, then...

If `cosA=mcosB`, then

A

`"cot" (A+B)/(2) = (m+1)/(m-1) "tan" (B-A)/(2)`

B

`"tan " (A+B)/(2) = (m+1)/(m-1) "cot " (B-A)/(2)`

C

`"cot" (A +B)/(2)= (m+1)/(m-1) "tan " (A-B)/(2)`

D

None of these

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The correct Answer is:
A
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