If tanbeta=costhetatanalpha, then "tan...

If `tanbeta=costhetatanalpha`, then `"tan"^(2)(theta)/(2)`=

A

`(sin (alpha +beta))/(sin (alpha- beta))`

B

`(cos (alpha- beta))/(cos (alpha + beta))`

C

`(sin (alpha- beta))/(sin (alpha + beta))`

D

`(cos (alpha +beta))/(cos (alpha- beta))`

Verified by Experts

The correct Answer is:

C

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