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sin 36^(º)sin 72^(º) + 108^(º) sin 144^(...

`sin 36^(º)sin 72^(º) + 108^(º) sin 144^(º) = `

A

`1//4`

B

`1//16`

C

`3//4`

D

`5//16`

Text Solution

Verified by Experts

The correct Answer is:
D
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sin 36^(º)sin 72^(º) sin108^(º) sin 144^(º) =

sin36^(@)sin72^(@)sin108^(@)sin144^(@)=

sin36^(@)sin72^(@)sin108^(@)sin144^(@)=

sin36^(@).sin72^(@).sin108^(@).sin144^(@)=?

Prove that: "sin"(pi)/(5)"sin"(2pi)/(5)"sin"(3pi)/(5)"sin"(4pi)/(5)=(5)/(16) "sin"36^(@) "sin"72^(@) "sin"108^(@) sin 144^(@)=(5)/(16) .

Prove that: sin36^(@)s in72^(0)s in108^(0)s in144^(0)=(5)/(16)

sin36^(@)sin72^(@)sin108^(@)sin144^(@)=(5)/(16)

Prove that cos 36^(@) cos 72^(@) cos 108^(@) cos 144^(@)=1//16 .