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(1+ "cos "(pi)/(8)) (1+ "cos"(3pi)/(8)) ...

`(1+ "cos "(pi)/(8)) (1+ "cos"(3pi)/(8)) (1+ "cos" (5pi)/(8)) (1+ "cos " (7pi)/(8))`=

A

`1//2`

B

`1//4`

C

`1//8`

D

`1//16`

Text Solution

Verified by Experts

The correct Answer is:
C
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