In triangleABC, (cos2A)/(a^(2))-(cos2B)/...

In `triangleABC, (cos2A)/(a^(2))-(cos2B)/(b^(2))=`

A

`a^2-b^2`

B

`(1)/(a^2-b^2)`

C

`(1)/(a^(2))-1/(b^2)`

D

`a^2+b^2`

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The correct Answer is:

C

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