If sin[pi/4.cottheta]=cos[pi/4tantheta],...

If `sin[pi/4.cottheta]=cos[pi/4tantheta]`, then `theta` =

A

`n pi + pi/4`

B

`2npi pm pi/4`

C

`npi - pi/6`

D

`2npi pm pi/6`

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The correct Answer is:

A

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