In any DeltaABC under usual notation, a(...

In any `DeltaABC` under usual notation, `a(bcosC-c cosB)`=

A

`b^2 - c^2`

B

`c^2 - b^2`

C

`(b^2-c^2)/2`

D

`(c^2-b^2)/(2)`

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The correct Answer is:

A

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