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IN triangleABC, (cosC+cosA)/(c+a)+(cosB)...

IN `triangleABC, (cosC+cosA)/(c+a)+(cosB)/(b)=`

A

`1/a`

B

`1/b`

C

`1/c`

D

`(c+a)/(b)`

Text Solution

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The correct Answer is:
B
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