In a DeltaABC, AD is the altitude from A...

In a `DeltaABC, AD` is the altitude from A. Given `bgt,c angleC=23^(@) and AD=(abc)/(b^(2)-c^(2))`, then `angle B=`....

A

`67^@`

B

`44^@`

C

`113^@`

D

None of these

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

In a triangle ABC, AD is the altitude from A. If b gt c . angleC = 23^(@) and AD = (abc)/(b^(2) - c^(2), " then " angle B =

In triangle ABC,AD is the altitude from A If b>c,/_C=23^(0), and AD=(abc)/(b^(2))-c^(2) then /_B=

In a triangle ABC,AD is the altitude form- abcA (Fig.12.9). Given b>0,2C=23^(@) and AD=(abc)/(b^(2)-c^(2)) then /_B. is equal to

In a ABC,AD is the altitude from A such that AD=12cm.BD=9cm and DC=16 cm.Examine if ABC is right angled at A

In a DeltaABC,angleC=60^(@) , then (1)/(a+b)+(1)/(b+c) is equal to

In a triangle ABC, if the median and altitude from A trisect angle A, then (B-C) is (in degrees) equal to……….

In DeltaABC," if " angleC=90^(@)," then " (a+c)/(b)+(b+c)/(a) is equal to :

In a Delta ABC , the median AD is perpendicular to AC. If b = 5 and c = 11, then a =

In a Delta ABC,B=(pi)/(8) and C=(5 pi)/(8) and the altitude AD=h. Then h: a is equal to