Find the sum to n terms of the series: 3...

Find the sum to `n` terms of the series: `3/(1^^2 .2^2)+5/(2^2 .3^2)+7/(3^2 .4^2)+`

A

`(n^2-2n)/((n+1)^2)`

B

`(n^2-2)/((n+1)^2)`

C

`(n^2+2n)/((n+1)^2)`

D

`(n^2+2)/((n+1)^2)`

Verified by Experts

The correct Answer is:

C

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