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Given sum of the first n terms of an A. ...

Given sum of the first `n `terms of an `A. P.` is `2n +3n^2`. Another `A. P.` is formed with the same first term and double of the common difference, the sum of `n` terms of the new `A. P.` is:

A

`n+4n^2`

B

`6n^2-n`

C

`n^2 +4n`

D

`3n+2n^2`

Text Solution

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The correct Answer is:
B
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