Home
Class 11
MATHS
Let a1, a2, a3...a49 be in AP such that ...

Let `a_1, a_2, a_3...a_49` be in AP such that `sum_(k=0)^12(a_4k+1)=416` and `a_9+a_43=66` If `a_1^2+a_2^2+...+a_17^2=140m` then m is equal to (1) 66 (2) 68 (3) 34 (4) 33

A

34

B

33

C

66

D

68

Text Solution

Verified by Experts

The correct Answer is:
A
Promotional Banner

Similar Questions

Explore conceptually related problems

Let a_(1),a_(2),a_(3)...a_(49) be in AP such that sum_(k=0)^(12)(a_(4)k+1)=416 and a_(9)+a_(43)=66 If a_(1)^(2)+a_(2)^(2)+...+a_(17)^(2)=140m then m is equal to (1)66(2)68(3) 34(4)33

a_1, a_2, a_3 …..a_9 are in GP where a_1 lt 0, a_1 + a_2 = 4, a_3 + a_4 = 16 , if sum_(i=1)^9 a_i = 4 lambda then lambda is equal to

If a_1, a_2, a_3 ,........ are in A.P. such that a_1 + a_5 + a_10 + a_15 + a_20 + a_24 = 225 , then a_1 + a_2+ a_3 + ......+ a_23 +a_24 is equal to

Let a_1,a_2,a_3 …. a_n be in A.P. If 1/(a_1a_n)+1/(a_2a_(n-1)) +… + 1/(a_n a_1) = k/(a_1 + a_n) (1/a_1 + 1/a_2 + …. 1/a_n) , then k is equal to :

Let a_1, a_2, …, a_21 be an AP such that sum_(n=1)^20 1/(a_n a_(n+1)) = 4/9 . if the sum of this AP is 189, then a_6a_16 is equal to :

Let a_1, a_2, …, a_21 be an AP such that sum_(n=1)^20 1/(a_n a_(n+1)) = 4/9 . if the sum of this AP is 189, then a_6a_16 is equal to :

Let a_1,a_2,a_3…… ,a_n be in G.P such that 3a_1+7a_2 +3a_3-4a_5=0 Then common ratio of G.P can be

If a_1,a_2,……….,a_(n+1) are in A.P. prove that sum_(k=0)^n ^nC_k.a_(k+1)=2^(n-1)(a_1+a_(n+1))