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The sum of first n terms of the series 1...

The sum of first n terms of the series `1^(2) + 2.2^(2) + 3^(2) + 2.4^(2) + 5^(2) + 2.6^(2)+…` is `(n (n + 1)^(2))/(2)` when n is even. When n is odd the sum is

A

`(n(n+1)^2)/2`

B

`1/2 n^2(n+1)`

C

`n(n+1)^2`

D

None of these

Text Solution

Verified by Experts

The correct Answer is:
B
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