Home
Class 11
MATHS
Three numbers are in an increasing geome...

Three numbers are in an increasing geometric progression with common ratio r. If the middle number is doubled, then the new numbers are in an arithmetic progression with common difference d. If the fourth term of GP is `3 r^(2)`, then `r^(2)` - d is equal to :

A

`7-sqrt3`

B

`7+3sqrt3`

C

`7-7sqrt3`

D

`7+sqrt3`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

The sides of a triangle are in geometric progression with common ratio r lt 1. If the triangle is a right-angled triangle, then r is given by

Suppose the sides of a triangle form a geometric progression with common ratio r. Then r lies in the interval-

Three terms forms an increasing G.P with ratio r . If the second term of the given G.P is double then the new series are in A.P with common difference d also the 4th terms of G.P is 3r^2 then the value of (r^2-d) is

The sides of a triangle are in geometric progression with common ratio rgt1 . If the triangle is a right angled triangle, then r^(2) is given by ?

Three positive numbers form an increasing GP. If the middle term in this GP is doubled, then new numbers are in AP. Then, the common ratio of the GP is

If the sum of 'n' terms of an arithmetic progression is S_(n)=3n +2n^(2) then its common difference is :

Three positive numbers form an increasing GP. If the middle terms in this GP is doubled, the new numbers are in AP. Then, the common ratio of the GP is