The fixed point P on the curve y=x^(2)-4...

The fixed point P on the curve `y=x^(2)-4x+5` such that the tangent at P is perpendicular to the line `x+2y-7=0` is given by

A

(3, 2)

B

(2, 1)

C

(3, -2)

D

(2, -3)

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The correct Answer is:

A

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