Home
Class 11
MATHS
The equation of the circle of radius 5 a...

The equation of the circle of radius 5 and touching the coordinates axes in third quadrant, is

A

`(x- 5)^(2) + (y+5)^(2) = 25`

B

`(x+ 4)^(2) + (y+4)^(2)= 25`

C

`(x+6)^(2) + (y+6)^(2)= 25`

D

`(x+ 5)^(2) + (y+5)^(2)= 25`

Text Solution

Verified by Experts

The correct Answer is:
D
Promotional Banner

Similar Questions

Explore conceptually related problems

Equation of the circle of radius 5 which touches both the coordinate axes is

Find the number of sphere of radius r touching the coordinate axes.

What is the degree of the differential equation of all circles touching both the coordinate axes in the first quadrant?

Equation of circle of radius 5, touching both co-ordinate axes , and passing through (1,2). Is

find the equation of cicle in the following case touches both the coordinate axes in first quadrant and having radius = 1 units

Equation of a circle of radius 3 ,touching the coordinate axes,no portion of which lies below x -axis is

A circle of radius 6 units touches the coordinates axes in the first quadrant.Find the equation of its image in the line mirror y=0

The equation of the circle in the third quadrant touching each co-ordinate axis at a distance of 2 units from the origin is

The equation of circle passing through (-1,-2) and touching both the axes is