The equation of the conic with focus at ...

The equation of the conic with focus at `(1,-1),` directrix along `x -y + 1=0` and with eccentricity `sqrt2,` is

A

`x^(2) -y^(2)=1`

B

xy=1

C

`2xy-4x+ 4y+1= 0`

D

`2xy +4x- 4y-1= 0`

Verified by Experts

The correct Answer is:

C

Similar Questions

Explore conceptually related problems

The equation oi the conic with focus at (1,-1) directrix along x-y+1=0 and eccentricity sqrt(2) is xy=1 b.2xy+4x-4y-1=0cx^(2)-y^(2)=1 d.2xy-4x+4y=1=0

The equation of conic with focus (-1,1) ,directrix x-y-1=0 and e=2 is

The equation of the parabola with focus (1,-1) and directrix x + y + 3 =0 is

The equation of conic section whose focus is at (-1 , 0), directrix is the 4x-3y+2=0 and eccentricity 1//sqrt2 1, is

the equation of the ellipse whose foucs is S(1,-1) directrix the line x-y-3=0 and eccentricity 1//2 , is

FInd the equation of the parabola The focus at (1,1) the directrix x-y=3

The equation of the ellipse whose focus is (1,-1), directrix x-y-3=0 and eccentricity equals (1)/(2) is :